What is the vertex of y=2x^2-8x+6?

the easiest way in which we can find the vertex is to rewrite the given y=2x^2-8x+6 in the form y-k =a(x-h)^2, where (h,k) is the vertex.  

y=2x^2-8x+6 can be rewritten as   y = 2(x^2 - 4x                 ) + 6

Completing the square,   y = 2(x^2 - 4x +4 - 4                ) + 6

Then y = 2(x-2)^2 - 2.  Comparing this to a(x-h)^2, we see that h=2 and k=2.  Thus the vertex is at (2, 2).