Question 2(Multiple Choice Worth 2 points)(10.06 MC)Compare the functions shown below:f(x) = 4 sin (2x − π) − 1 g(x)x y−1 60 11 −22 −33 −24 15 6h(x) = (x − 2)2 + 4Which function has the smallest minimum y-value? f(x) g(x) h(x) Both f(x) and g(x) have the same minimum y-value.

Answer:1. f(x)=4 sin (2 x-π)-1  =4 sin [-(π-2 x)] -1  = -4 sin 2 x -1-1 ≤ sin 2 x ≤1f(x) is minimum, when, sin 2 x=1= -4 × 1 -1= -5→Minimum value of f(x).2. Minimum y value of g(x) by looking at the table is , g(x)=-3→Minimum3. h(x)=(x-2)²+4As, (x-2)², will yield always a positive value.So, minimum of h(x), will be at , x=2h(2)=(2-2)²+4=4→MinimumAmong the three function given, f(x) has minimum y -value,equal to -5.Option A: f(x)