A company plans to enclose three parallel rectangular areas for sorting returned goods. the three areas are within one large rectangular area and 10641064 yd of fencing is available. what is the largest total area that can be​ enclosed?

First get the perimeter Perimeter: 2l + 2w = 1064 yd   The region inside the fence is the area Area: A = lw   We need to solve the perimeter formula for either length or width. 2l + 2w = 1064 yd 2w = 1064 yd – 2l W = 1064– 2l / 2 W = 532 – l   Now substitute than to the area formula A = lw A = l (532 – l) A = 532 – l^2   Since the equation A represents a quadratic expression, rewritte the expression with the exponents in descending order A(l) = -l^2 + 532l   Then look for the value of the x coordinate   l = -b/2a l = -532/2(-1) l = -532/-2 l = 266 yards   Plugging in the value into our calculation for area: A(l) = -l^2 + 532 A(266) = -(266)^2 + 532 (266) A(266) =  70756+ 141512 = 70756 square yards.   Thus the largest area that could encompass would be a square where each side has a length of 266 yards and a width of:
W = 532 – l = 532 – 266 = 266