In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 60 pound weight if the bar is 24 feet long?A) 9B) 15C) 12

Answer:15 feetStep-by-step explanation:Given : In this fulcrum, the weights are perfectly balanced. To Find: How far must the fulcrum be located from the 60 pound weight if the bar is 24 feet long?Solution:To make the weights perfectly balanced torque must be equal [tex]Torque = Force \times d[/tex]Where [tex]Force = Mass \times Acceleration[/tex]Let a be the accelerationd= Distance between the pivot and the acting point.Let x be the distance from 60 pound weight where fulcrum is locatedSince we are given that Length of bar = 24 feet.So,Distance of fulcrum from 100 pound weight = 24-xNow torque for 60 pound weight :[tex]Torque = 60a \times x[/tex]Now torque for 100 pound weight.[tex]Torque =100a \times (24-x)[/tex]Now to maintain the equilibrium i.e. To make the weights perfectly balanced[tex]60a \times x =100a \times (24-x)[/tex][tex]60x = 2400-100x[/tex][tex]160x = 2400[/tex][tex]x = \frac{2400}{160}[/tex][tex]x = 15[/tex]Hence The fulcrum must be located 15 feet from the 60 pound weight if the bar is 24 feet long.