Expressed powers are those that aref(x) = 5x + 3; g(x) = 6x - 5 Find f/g. (f/g)(x) = Quantity six x minus five divided by five x plus three. domain {x|x ≠ Five over six. } (f/g)(x) = Quantity five x plus three divided by six x minus five. domain {x|x ≠ Three over five } (f/g)(x) = Quantity five x plus three divided by six x minus five.domain {x|x ≠ Five over six. } (f/g)(x) = Quantity six x minus five divided by five x plus three. domain {x|x ≠ - Three over five. }

Answer: (f/g)(x) = Quantity five x plus three divided by six x minus five.domain {x|x ≠ Five over six. }

Explanation:

1) (f/g)(x) = f(x) / g(x)

2)

  f(x)         5x + 3
-------- = ------------
  g(x)        6x - 5

3) Since the division by 0 is not defined, the domain is restricted to 6x - 5 ≠ 0.

Therefore you must solve 6x - 5 = 0 to exclude the value of x for which the denominator becomes 0:

6 x - 5 = 0 => 6x = 5 => x = 5 / 6.

So, the domain is all x | x ≠ 5/6.