Simplify the expression The root of negative nine over the quantity of three minus two i plus the quantity of one plus five i.

This will be:
[√9]/[(3-2i)+(1+5i)]
simplifying  the above we get:
√9/(3+1-2i+5i)
=√9/(4+3i)
rationalizing the denominator we get:
√9/(4-3i)×(4-3i)/(4-3i)
=[√9(4-3i)]/(16+9)
=[3(4-3i)]/25
=(12-9i)/25

Answer: (12-9i)/25