What is the slope-intercept form of the equation of the line that passes through the point (–6, 1) and is perpendicular to the graph of 2x + 3y = –5?y = x – 8y = x + 1y = x + 1y = x + 10

When some line named l1 is perpendicular to some other line named l2 ,
then there is slope coefficijent 

S1= - 1/ S2

In our case we must first transform given line from standard form to slope form

2x+3y= -5 => 3y = - 2x-5 => y = (-2/3)x -5

The slope coefficijent od the given line is S= - 2/3
 Then the slope coefficijent of the requested line is 

S1= - 1/(-2/3) => I suppose that you know to solve double fraction
S1=3/2
The equation for the line which passes through one point is 
y-y1 = S1 (x-x1)  => y-1 = 3/2 (x-(-6)) => y-1 =3/2 (x+6) 
We will multiply both sides of the equation with number 2 and get
2y-2=3x+18 => 2y=3x+18+2 => 2y = 3x+20
When we divide the both sides with number 2 we finally get
y= (3/2)x+10.
Good luck!!!!