tarun and vinay start walking at the same time fom two opposite ends of a track that is 50 km long. tarun is walking at a speed of 10 kmph and vinay is running at 20 kmph. how long aer t start from their respective spots will t meet?
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Answer:
Aer 1.666 hour both tarun and vinay will meet each otherWe have given distance between Tarun and Vinay is 50 km So distance d = 50 km Speed of tarun = 10 km/hrAnd speed of vinay = 20 km/hr So relative speed = 20+10 = 30 km/hr ( As both are waking in opposite direction ) We have to fond the time aer which t will meet to each other Time is given by \(time=\frac{}distance{}{}speed{}=\frac{}50{}{}30{}=1.666hour\)So aer 1.666 hour both will meet to each other Learn more Rain x starts from a place at a speed of 50 kmph. aer one hour another train y starts from the same place at the speed 70 km/hr. aer how much time will y cross aer starting of train x?https:///question/4690108
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algebra
10 months ago
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