If f(x) and its inverse function, f–1(x), are both plotted on the same coordinate plane, what is their point of intersection? (0, –2) (1, –1) (2, 0) (3, 3)

Answer:[tex]\text{(3,3) is point of intersection of  } f^{-1}(x)=f(x)[/tex]Step-by-step explanation:If f(x) and it's inverse function [tex]f^{-1}(x)[/tex] plot on same coordinate plane. Both graph intersect at line y=x because y=x is line of symmetry of inverse function. Intersection of  [tex]f^{-1}(x)[/tex] and f(x) would be x and y coordinate same. Therefore, [tex]f^{-1}(x)=f(x)=x[/tex]We are given four options. Let we check each one. Option 1: (0,-2)x=0 and y=-2 , 0≠-2This is false. Option 2: (1,-1)  x=1 and y=-1 , 1≠-1This is false. Option 3: (2,0)  x=2 and y=0 , 2≠0This is false. Option 4: (3,3)  x=3 and y=3 , 3=3This is true. Thus, (3,3) is point of intersection of [tex]f^{-1}(x)=f(x)[/tex]