A pump with average discharge of 30L/second irrigate 100m wide and 100m length field area crop for 12 hours. What is an average depth of irrigation in mm unIt?

To find the average depth of irrigation in millimeters (mm), you can use the following formula: $$\text{Average Depth (in mm)} = \frac{\text{Total Volume of Water}}{\text{ Area of the Field}}$$ First, let's calculate the total volume of water delivered by the pump in 12 hours. The pump discharges 30 liters per second, so in 12 hours: $$\text{Total Volume} = \text{Discharge Rate (in liters/second)} \times \text{Time (in seconds)}$$ $$\text{Total Volume} = 30 \text{ L/s} * (12 \text{ hours} * 3600 \text{ seconds/hour})$$ Now, calculate the total volume in liters: $$\text{Total Volume} = 30 L/s \times 43,200 seconds = 1,296,000 liters$$ Now, let's convert this total volume from liters to cubic meters (1 cubic meter = 1000 liters): $$\text{Total Volume (in cubic meters)} = \frac{1,296,000 liters}{ 1000} = 1,296 \text{cubic meters}$$ Next, you need to find the area of the field, which is 100 meters wide and 100 meters long: Area of the Field (in square meters) = Width (m) * Length (m) = 100 m * 100 m = 10,000 square meters Now, you want to express the area in square millimeters: Area of the Field (in square millimeters) = Area of the Field (in square meters) * 1,000,000 (since 1 square meter = 1,000,000 square millimeters) $$\text{Area of the Field (in square millimeters)} = 10,000 m^2 * 1,000,000 = 10,000,000,000 \text{ square millimeters}$$ Now, you can find the average depth of irrigation: $$\text{Average Depth (in mm)} = \frac{\text{Total Volume (in cubic meters)}} {\text{Area of the Field (in square millimeters)}}$$ $$\text{Average Depth (in mm)} = \frac{1,296 }{ 10,000,000,000}$$ Average Depth (in mm) = 0.0000001296 mm (rounded to four decimal places) So, the average depth of irrigation in millimeters is approximately 0.0000001296 mm.