Write the point-slope form of the equation of the line with a slope of - 2 and an x-intercept of - 1. Include your work in your final answer.Please helps and show how.

well, if the x-intercept is at x = -1, what's y?  well, is an x-intercept, y = 0, so the point is -1, 0.

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -1}}\quad ,&{{ 0}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies -2 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-0=-2[x-(-1)]\implies y=-2(x+1)[/tex]