Write the equation in standard form for the circle passing through ( - 6,0) centered at the origin.
Question
Answer:
The equation for a circle:[tex]\boxed { \boxed { (x - a)^2 + (y - b)^2 = r^2}}[/tex]
Since the centre is at (0,0), then the equation will be:
[tex]\boxed { \boxed {x^2 + y^2 = r^2}}[/tex]
It passed through (-6, 0) :
[tex] (-6)^2 + 0^2 = r^2[/tex]
[tex] r^2 = 6^2[/tex]
[tex]r = 6[/tex]
The radius is 6, therefore the equation of the circle is :
[tex]x^2 + y^2 = 6^2[/tex]
[tex]\boxed { \boxed { x^2 + y^2 = 36}}[/tex]
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