Write an equation for the line that is parallel to the given line and that passes through the given point.y equals five halves x minus 10; the point negative 6, negative 29A. y equals five halves x plus one hundred thirty three halvesB. y equals five halves x minus 14C. y equals two fifths x minus 14D. y equals negative two fives x plus 14

Answer:The correct option is B.Step-by-step explanation:The slope intercept form of a line is[tex]y=mx+b[/tex]where, m is slope and b is y-intercept.The given equation is[tex]y=\frac{5}{2}x-10[/tex]It means the slope of the line is 5/2 and y-intercept is -10.The slope of two parallel lines is same. So, the slope of required line is 5/2.The equation of required line is[tex]y=\frac{5}{2}x+b[/tex]It is given that the line passes through the point (-6,-29).[tex](-29)=\frac{5}{2}(-6)+b[/tex][tex]-29=-15+b[/tex][tex]-29+15=+b[/tex][tex]-14=b[/tex]The y-intercept of required line is -14. So the equation of required line is[tex]y=\frac{5}{2}x-14[/tex]Therefore the correct option is B.