What is the surface area of this triangular prism rounded to the nearest tenth? A) 63.3 cm2 B) 75.6 cm2 C) 85.7 cm2 D) 97.2 cm2

The answer is C.
SA = bh + (s1 + s2 + s3)H
SA = (6.8)(5.1) + (6.8 + 5.1 + 8.5)(2.5) = 85.68