What is the surface area of a cone that has a radius of 8 feet and a slant height of 12 feet? (Use 3.14 for π.)301.44 ft 2502.4 ft 2200.96 ft 2803.84 ft 2​

Answer:Surface area of cone is [tex]502.4\ ft^2[/tex]Step-by-step explanation:Given:radius of a cone (r) = 8 feetslant height of cone (l) = 12 feetWe need to find the surface area of cone.Total surface area of cone = Area of circle [tex]+[/tex] Area of curved surfaceNow we know that,Area of circle = [tex]\pi r^2[/tex]Area of curved surface = [tex]\pi rl[/tex]Hence Total surface area of cone = [tex]\pi r^2+\pi rl=\pi r(r+l) = 3.14 \times 8 (8+12)=3.14\times8\times20= 502.4 \ ft^2[/tex]Surface area of cone is [tex]502.4\ ft^2[/tex].