What is the perimeter of a parallelogram, if its area is 72 cm2 and the distances between the point of intersection of the diagonals and the sides are 3 cm and 4 cm?

Answer:The perimeter of a parallelogram is 42 cm.Step-by-step explanation:The area of a parallelogram is 72 cm².The formula for area of a parallelogram is[tex]A=base \times height[/tex]It is given that the distances between the point of intersection of the diagonals and the sides are 3 cm and 4 cm.The distance between point of intersection of the diagonals and the opposite  sides are same.[tex]h_1=3+3=6cm[/tex][tex]A=b_1\times h_1[/tex][tex]72=b_1\times 6[/tex][tex]b_1=12cm[/tex]The measure of a side is 12 cm.[tex]h_2=4+4=8cm[/tex][tex]A=b_2\times h_2[/tex][tex]72=b_2\times 8[/tex][tex]b_2=9cm[/tex]The measure of another side is 9 cm.The perimeter of a parallelogram is[tex]P=2(b_1+b_2)=2(12+9)=42[/tex]Therefore the perimeter of a parallelogram is 42 cm.