To solve this system of equations by elimination, what operation could be used to eliminate the y-variable and find the value of x? 2x − 4y = 6 −3x + 3y = 12

2x - 4y = 6
-3x + 3y = 12

In order to find x (first) you need to eliminate y

3( 2x - 4y = 6)
4( -3x + 3y = 12)

6x -12y = 18
-12x +12y = 48

y cancels out and you should now have

6x - 12x = 18 +48
Simplify the equation;

-6x = 66
Divide both sides by - 6 to get x by itself,

x = 11