the value 5 is a an upper bound for the zeros of the function shown below f(x)=x^4+x^3-11x^2-9x+18A. TRUEB. FALSE

Answer:Answer to this question is TRUE.Step-by-step explanation:The graph of the function:[tex]f(x)=x^4+x^3-11x^2-9x+18[/tex]  is attached to the answer.Clearly by looking at the graph we could see that the zeros of the function f(x) are -3, -2, 1 and 3.All the zeros are distinct." Also upper bound of a number 'p' means the set of all those numbers which are greater than 'p' ".Here 5 will be an upper bound for the zeros of the function f(x) since all the 4 zeros of f(x) are less than 5.Hence, the given statement that the value 5 is an upper bound for the zeros of the function f(x) is TRUE.