The cost of two tables and three chairs is 705$ if the table costs 40$ more than the chair find the cost of one table and two chairs

Chair= x
Table= x+40

2(x+40)+3x=705
2x+80+3x=705
5x+80=705
5x=705-80
5x=625
x= 625/5
x=125

1 chair costs $125
1 table costs $165

The cost of 1 table and two chairs-----> 165+125+125= $415