Suppose that a device has been created that launches objects at ground level and that its operation is modeled by the function h(x) = -4ײ + 256x, with h being the height (in meters) and x being the distance (in meters) What is the maximum height that the object reaches?
Question
Answer:
$$ h\left(x\right)=-4x^2+256x $$
then h'(x) = -8x+256
For critical point;
h'(x)=0
-8x+256=0
x=256/8=32
x=32
Now h''(x)=-8 which is less than 0, so the function give maximum value at x=32.
So the maximum height = $$ -4\times32^2+256\times32=\:4096 $$
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11 months ago
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