Solve the system by the elimination method. 3x - 2y - 7 = 0 5x + y - 3 = 0 To eliminate y, the LCM is 2. Which of the following is the resulting equations? 3x - 2y - 7 = 0 5x + y - 3 = 0 3x - 2y - 7 = 0 -10x - 2y + 6 = 0 3x - 2y - 7 = 0 10x + 2y - 6 = 0

Next time, please share your system of linear equations by typing only one equation per line:

3x - 2y - 7 = 0 5x + y - 3 = 0  NO

3x - 2y - 7 = 0
5x + y - 3 = 0                          YES

Mult. the 2nd equation by 2 so as to obtain 2y, which will be cancelled out by  - 2y in the first equation:

  3x - 2y - 7 = 0
2(5x + y - 3 = 0)

Then:

  3x - 2y - 7 = 0
10x +2y - 6 = 0
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13x - 13 = 0, so that x = 1.  Find y by subbing 1 for x in either of the 2 given equations.