Rose counted her money and found that her 25 coins which were nickels, dimes, and quarters were worth $3.20. the number of dimes exceeded the number of nickels by 4. how many coins of each kind did she have?
Question
Answer:
N = number of nickles D = number of dimes = N+4
Q = number of quarters
= 25-N-D
= 25-N-(N+4)
= 21-(2N)
Add the coins to get $3.20
(N*$0.05) + (D*$0.10) + (Q*$0.25) = $3.20
Expressing D and Q in terms of N:
(N*$0.05) + ((N+4)*$0.10) + (21-2N)*$0.25=$3.20
Solve for N. Then plug N into the equations for D and Q
solved
general
10 months ago
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