NEED ANSWER NOW PLEASEEEEEEEEEEEEEWhich statement is true about the solution of (picture below)?A. x = –2 is an extraneous solution, and x = 6 is a true solution.B. x = 6 is an extraneous solution, and x = –2 is a true solution.C. Both x = –2 and x = 6 are extraneous solutions.D. Both x = –2 and x = 6 are true solutions.

[tex] \sqrt[3]{x {}^{2} - 12 } = \sqrt[3]{4x} [/tex]
Cube by both sides:
[tex]x {}^{2} - 12 = 4x[/tex]
[tex]x {}^{2} - 4x - 12 = 0[/tex]
[tex](x - 6)(x + 2) = 0[/tex]
The solutions are:
[tex]x = 6 \: \: and \: \: x = - 2[/tex]
The answer D is correct.