Medal to correct answer!!A game of "Doubles-Doubles" is played with two dice. If a player rolls doubles, the player earns 3 points and gets another roll. If the player rolls doubles again, the player earns 9 more points. How many points should the player lose for not rolling doubles in order to make this a fair game?3/527/359/101

Question
Answer:
The answer is 27/35.
The probabilities are the following:
one double= 5/36
two doubles =1/36
no doubles = 1/6 

The formula will be,
12/36 + 5[(3-x)/36] - (5)(x/6) = 0
x=27/35
solved
general 11 months ago 8916