In the triangle, bc=12 cm and tan c =0.583. what is the length of the hypotenuse, to the nearest tenth of a centimeter

Given that BC=12 cm and tan C=0.583, the value of the hypotenuse will be given as follows:
BC is the adjacent, the height AB will be given by
AB/BC=tan C
thus
AB/12=0.583
AB=12*0.583
AB=6.996
hence using Pythagorean theorem:
c^2=b^2+a^2
thus;
c^2=6.996^2+12^2
c^2=192.944016
c=13.890~14 cm (to the nearest centimeter)