In a class of 147 students, 95 are taking math(m), 75 are taking science (s), 52 are taking both math and science. What is the probability of randomly choosing a student who is taking neither math nor science? Round your answer to the nearest tenth

Subtract 52 from m, s, and the total amount of students.. 52 is the amount of students that would take both math and science. m now equals 43, s now equals 23, and the total students remaining is 95.

Since the criteria wants you to exclude students that take math or science, add m and s together. 

[tex]43 + 23 = 66[/tex]

This is the total amount of students that take math or science.

To find the probability of picking a student that doesn't take math or science, subtract 66 from the total amount of students. 

[tex]95 - 66 = 29[/tex]

Take this amount and divide by the total amount of students again.

[tex] \frac{29}{95} = 0.3052[/tex]

Convert the decimal into a percentage.

[tex]0.3052 = 30.52[/tex] %

There is a 30.52% chance of picking a student that doesn't take math nor science.