How do you find zeros when given a quadratic relation in vertex form

In order to find the zeros in a quadratic in vertex form, you need to follow a number of steps. They have been outlined for you along with a sample problem. y = (x - 2)^2 - 16After getting the original form, you can place a 0 in for y. In is where the graph will cross the x-axis, so it is where you will find both of your zeros. 0 = (x - 2)^2 - 16Now take the constant and add it to both sides. In this equation, -16 is your constant. So, we'll add 16 to both sides to begin to solve. 16= (x - 2)^2Now we can take the square root of both sides. After we do so, we take both the positive and negative version of what we get. This is because both 4 and -4 squared is equal to 16. +/-4 = x - 2Now we add 2 to both sides to get us what is left of x. 2 +/- 4 = xNow that we have a final form such as this, we can separate and get two answers for our two zeros. 2 + 4 = 62 - 4 = -2