HELP ME PLEASE!!!!!!The body of a 154-pound person contains approximately 2 X 10^-1 milligrams of gold and 6 X 10^1 milligrams of aluminum. Based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body?

Question

Answer:

let a be aluminum and g be gold and k how many times:

2*10⁻¹mg a+ 6*10¹mg g= 154 lb

so a=kg

k=a/g

k=2*10⁻¹/6*10=1/300

a=1/300g

so Aluminum is 1/300 of gold.