Given a circle with measures of (C, d, and r) and a circle with measures of (C', d', and r'), what is C if d d' = 0.25 and C' = 16?

Mathematically, C’ = πd’ C’ =16, π = 22/7 ∴ 16 = 22d’/7 16 x 7 = 22d’ d' = (16 x 7) / 22 d’ = 112/22 d’ = 5.09   d d’ = 0.25 d’ = 5.09 ∴ d (5.09) = 0.25 d = 0.25/5.09 d = 0.05   Mathematically, C = πd π = 22/7, d = 0.05 ∴ C = 22/7 x 0.05 C = 0.16