Expand the following: 1/3(6/5x-3)

x in (-oo:+oo)

(1/3)*((6/5)*x-3) = 0

1/3*(6/5*x-3) = 0
( 1/3 )

1/3 = 0

x belongs to the empty set

( 6/5*x-3 )

6/5*x-3 = 0 // + 3

6/5*x = 3 // : 6/5

x = 3/6/5

x = 5/2

x = 5/2