does anyone know the answer???

Question
Answer:
Answer:a = √5 b ∈ (βˆ’βˆž,∞)Step-by-step explanation:(7 + 3√5)/(3 + √5) - (7 - 3√5)/(3 - √5) = a + b√5⇔ (7 + 3√5)(3 - √5)/(3 + √5)(3 -√5) - (7 - 3√5)(3 + √5)/(3 + √5)(3 -√5) = a + b√5 ⇔ (7 + 3√5)(3 - √5) - Β (7 - 3√5)(3 + √5)/(3 + √5)(3 -√5) = a + b√5⇔ 4√5/4 = a + b√5⇔ √5 = a + b√5 ⇔ b = (5 - a√5)/5 Replace b with (5 - a√5)/5 β‡’ a + Β (5 - a√5)/5 = √5⇔ a Γ— 5 + (5 - a√5)(5)/5 = √5 Γ— 5⇔ a Γ— 5 + 5 - a√5 = 5√5 ⇔ a Γ— 5 - √5 Γ— a = 5√5 - 5⇔ a(5 - √5) = 5√5 - 5⇔ a = √5
solved
general 10 months ago 1597