Convert the point slope equation y + 5 = - 3/4(x + 2) into standard form.

[tex]\bf y+5=-\cfrac{3}{4}(x+2)\implies y+5=-\cfrac{3}{4}x\left( -\cfrac{3}{4} \right)2\implies y+5=-\cfrac{3}{4}x-\cfrac{3}{2} \\\\\\ \cfrac{3}{4}x+y=-\cfrac{3}{2}-5\implies \stackrel{standard~form}{\cfrac{3}{4}x+y=-\cfrac{13}{2}}[/tex]