Calculate the sum of the first 550 natural numbers

The number series 1, 2, 3, 4, . . . . , 549, 550. The first term a = 1 The common difference d = 1 Total number of terms n = 550 So, Sum = n/2 x (a + Tn) = 550/2 x (1 + 550) = 303050/2 1 + 2 + 3 + 4 + . . . . + 549 + 550 = 151525 Therefore, 151525 is the sum of positive integers upto 550.