Any good mathematicians out there that can help me on this two problems? I'll give you brainliest plus the 25 points it comes with
Question
Answer:
Hello!! So we have for the first question standard form for slope=8/3; and coordinate point (-2,0)
So y-y1=m(x-x1)
y-0=8/3(x-(-2))
y=8/3x + 16/3
Now multiply through by 3/3 to clear fractions and we get standard form.
3y=8x+16 then rearrange and we get 8x-3y+16=0 is standard form.
Point slope form for (-5,6) and (3,-10)
y-y1=m(x-x1)
-10-6=m(3-(-5)) so -16=m8 so m= -8/16= -1/2
So now picking any coordinate point we get
y-(-10)=-1/2(x-3)
y=-1/2x +3/2 -10 so y= -1/2x +3/2 - 20/2 we finally get
y=-1/2x-17/3 in point slope form.
Hope this helps you!!! Any questions please ask!! Thank you so much!!
solved
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11 months ago
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