An astronomer wishes to measure on a photograph the distance between the image of a certain star and three other star images nearby. If eight images are nearby, how many choices of the three stars does he have?
Question
Answer:
8 C 3 = 8! / (3!(8 - 3)!) = 8! / (3! * 5!) = (8 * 7 * 6 * 5!) / (3! * 5!) = (8 * 7 * 6) / (6) = 56Β 56 choices.Β
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