A wire is stretched from the top of an 8 ft. pole to a bracket 5 ft. from the base of the pole. How long is the wire?
Question
Answer:
pathagorean theorem:[tex] {a}^{2} + {b}^{2} = {c }^{2} \\ {8}^{2} + {5}^{2} = {c}^{2} \\ 64 + 25 = {c}^{2} \\ 89 = {c}^{2} \\ \sqrt{89 } = \sqrt{ {c}^{2} } \\ the \: wire \: is \: 9.43ft[/tex]
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