A stadium has 49,000 seats. Seats sell dor $25 in Section A, $20 in Section B, and $15 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in $1,052,000 from each sold-out event. How many seats are in each section?

Answer:Section A has 24,500 seats.Section B has 14,400 seats.Section C has 10,100 seats.Step-by-step explanation:Let the number of seats in Section B be y and in Section C be z  seats. Number of seats in Section A is 1/2 * 49000 = 24,500.Also   y + z = 24,500....... (1)And using the costs of the tickets:25*24,500 + 20y + 15z = 1,052,000 20y + 15z = 1052000 - 25*2450020y + 15z =  439,500........ (2) Now multiply (1) by 20:20y  + 20z = 490,000             Subtracting-5z = - 50,500z = 10,100 and y = 24500 - 10,100= 14,400.