A sail is in the form of a right triangle that is three times as high it is wide. The sail is made from 24 square meters of materials. What is its height

Make an equation system based on the problem
First equation
An equation for "a right triangle that is three times as high it is wide" could be written as:
∴ h = 3b (b stands for the wide/base, h stands for the height)
Second equation
An equation for "The sail is made from 24 square meters of materials" could be written as:
∴ area = 24
   [tex] \frac{1}{2}bh=24 [/tex]

Solve the system of equation by substitution method.
Substitute h with 3b in the second equation, and we'll find the value of b
[tex] \frac{1}{2}bh=24 [/tex]
[tex]\frac{1}{2}b(3b)=24[/tex]
simplify
[tex] \dfrac{3 b^{2} }{2} =24[/tex]

Solve for b
3b² = 24 × 2
3b² = 48
  b² = 48/3
  b² = 16
  b = √16
  b = 4
The value of b is 4, therefore the base of the triangle is 4 meters wide.

Using first equation, find the value of h
h = 3b
h = 3(4)
h = 12
The height of the triangle is 12 meters