A rectangular law whose perimeter is 310 feet is fenced along 3 sides and expensive fencing along the lot cost $20 per foot and inexpensive fencing along with the 2 sides with costs only $4 per foot. The total cost of fencing along the three sides comes 22 thousand two hundred and sixty dollars

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Answer:
Sure, I can help you with that. Let's say the dimensions of the rectangular lot are x and y. The perimeter of the lot is 310 feet, so 2x + 2y = 310. We know that the total cost of fencing along the three sides is $22,260, and that the expensive fencing costs $20 per foot and the inexpensive fencing costs $4 per foot. Let's say that the length of the expensive fencing is a, and the length of the inexpensive fencing is b. We know that a + b = 2x, and that 20a + 4b = 22,260. Substituting the first equation into the second equation, we get 20a + 4(2x - a) = 22,260. Simplifying the equation, we get 16a = 22,260 + 8x. Dividing both sides of the equation by 16, we get a = 1,403.75 + 0.5x. Since 2x + 2y = 310, we know that x + y = 155. Substituting the value of a into this equation, we get x + 1403.75 + 0.5x = 155. Simplifying the equation, we get 1.5x = 15.25. Dividing both sides of the equation by 1.5, we get x = 10.17. Substituting this value of x into the equation a = 1,403.75 + 0.5x, we get a = 1,546.09. Therefore, the length of the expensive fencing is 1,546.09 feet, and the length of the inexpensive fencing is 10.17 feet. The total cost of the expensive fencing is 1,546.09 * $20 = $30,921.80. The total cost of the inexpensive fencing is 10.17 * $4 = $40.68. The total cost of the fencing is $30,921.80 + $40.68 = $30,962.48. So the answer is 30962.48
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