A prop for the theater club’s play is constructed as a cone topped with a half-sphere. What is the volume of the prop? Round your answer to the nearest tenth of a cubic inch. Use 3.14 to approximate pi.

The volume of the prop is calculated to be 1,875.6 cubic inches.Step-by-step explanation:Step 1:The prop consists of a cone and a half-sphere on top. We will have to calculate the volumes of the cone and the half-sphere separately and then add them to obtain the total volume.Step 2:The volume of a cone is determined by multiplying [tex]\frac{1}{3}[/tex] with π, the square of the radius (r²) and height (h). Here we substitute π as 3.14. The radius is 8 inches and the height is 12 inches.The volume of the cone: [tex]\frac{1}{3} \pi r^{2} h = \frac{1}{3} (3.14) (8^{2}) (12)= 803.84[/tex] cubic inches.Step 3:The area of a half-sphere is half of a full sphere. The volume of a sphere is given by multiplying [tex]\frac{4}{3}[/tex] with π and the cube of the radius (r³).Here the radius is 8 inches. We take π as 3.14.The volume of a full sphere[tex]= \frac{4}{3} \pi r^{3} = \frac{4}{3} (3.14) (8^{3} ) = 2,143.573[/tex] cubic inches.The volume of the half-sphere[tex]= \frac{2,143.573}{2} = 1,071.7865[/tex] cubic inches.Step 4:The total volume = The volume of the cone + The volume of the half sphere,The total volume =  [tex]803.84+1,071.7865 = 1,875.6265[/tex] cubic inches.Rounding this off, we get the volume of the prop as 1,875.6 cubic inches.