A city's population is represented by the function P=25,000(1.0095)t , where t is time in years.How could the function be rewritten to identify the daily growth rate of the population?What is the approximate daily growth rate?Drag and drop the choices into the boxes to correctly complete the table. If a value does not match, do not drag it to the table. Function Daily growth rateP=25,000(1.00951365)365t 0.003%P=25,000(1+0.0095)t365 0.0012% P=25,000(1+0.00951365)365t 0.95%

Answer:The approximate daily growth rate is 0.0026%The function can be rewritten as P = 25,000*[1.0095^(1/365)]^t, where now t is in daysStep-by-step explanation:Given the formula:P = 25,000*(1.0095)^t25,000 indicates the initial population, t is the time elapsed in years, and P is the population after t years. After 1 year the population will be:  P = 25,000*(1.0095)which is equivalent to:P = 25,000*100.95%that represents an increment of 0.95 % in a year. Given that the year has 365 days, then this represent a daily growth of 0.95/365 = 0.0026% Dividing t by 365 in the original expression, so that, time is expressed in days, we get:P = 25,000*(1.0095)^(t/365)Which can be rewritten as:P = 25,000*[1.0095^(1/365)]^tP = 25,000*(1.000026)^tThat represents a daily growth rate of 0.0026% and now t is in days