A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is how many units. The point (-7,? ) lies on this circle.
Question
Answer:
we know thatthe equation of a circle is
(x-h)²+(y-k)²=r²
(h,k) is the center----------> (-3,2)
the radius is the distance point (-3,2) and point (1, 5)
d=√(5-2)²+(1+3)²-------> d=√9+16----------> d=5
radius=5 units
equation is
(x+3)²+(y-2)²=25
for x=-7
(-7+3)²+(y-2)²=25-------> 16+y²-4y+4=25
y²-4y-5=0
using a graph tool -------> to resolve the second order equation
see the attached figure
the solution is
y1=-1
y2=5
the point will be
(-7,-1)
(-7,5)
solved
general
10 months ago
3244