A change jar contains nickels dimes and quarters totaling and amount of $1.90 the amount of nickels is one more than twice the number of Dimes the number of quarters is one half the total number of nickels and dimes find the number of each coin in the change jar

Answer:Given belowStep-by-step explanation:We know Nickel is 5% of a dollar and dime is 10% of dollar while quarter is 25% of dollarGiven Let x be the no. of Dimestherefore nickels be 2x+1Quarter=[tex]\frac{1}{2}(2x+1+x)=\frac{1}{2}(3x+1)[/tex]Also total worth of coins is $1.90x(0.1)+(2x+1)0.05+[tex]\frac{1}{2}(3x+1)(0.25)=1.9[/tex]115x+35=380x=3therefore no of nickels =2*3+1=7Quarter=5