A bicyclist was traveling from the village to the railroad station with a speed of 15 mph and he was coming back to the village with a speed of 10 mph. Find the distance from the village to the railroad station, if it’s known that it took 1 more hour for the bicyclist to get back to the village.

Since, a bicyclist was traveling from the village to the railroad station with a speed of 15 mph and he was coming back to the village with a speed of 10 mph.Let the time taken in traveling from village to the railroad station be 't' hoursDistance is calculated by the formula:[tex] d= s \times t [/tex]So, the distance traveled from village to the railroad station is:[tex] d=15 \times t [/tex]Since, the time taken in traveling from railroad station to the village is 1 hour more = 't+1' hoursSo, the distance traveled from railroad station to the village is: [tex] d=10 \times (t+1) [/tex]Therefore, distance traveled from village to railroad station is equals to the distance traveled from railroad station to the village.So, [tex] 15 \times t=10(t+1) [/tex][tex] 15t=10t+10 [/tex][tex] 5t=10 [/tex]So, t=2Therefore, distance from village to railroad station = [tex] 15 \times t [/tex]= [tex] 15 \times 2 [/tex]= 30 miles.Therefore, the distance from village to railroad station is 30 miles.