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Answer:b.) The graph's x-intercepts are similar to ½(x - 5)(x + 2).a.) [-2, 0], [5, 0]__________________________________________________________b.) The graph has a maximum value because the graph opens down [-2 = A].a.) [-3, -4]__________________________________________________________d) [0, -5]c) -2 = xb) [-2, -9] → [h, k]a) -1, 5 = xExplanation:b) Both graphs have the binomial of [x - 5][x + 2], so the x-intercepts never altered.a) Set the binomial equal to zero, and you will get your x-intercepts of [-2, 0] and [5, 0].__________________________________________________________b) When A is negative, your graph will have a maximum value [opens down], whereas when A is positive, your graph will have a minimum value [opens up].a) According to the Vertex Formula, y = A[X - H]² + K, [H, K] represents the vertex, plus, -H gives you the OPPOSITE TERMS OF WHAT THEY REALLY ARE, so be EXTREMELY CAREFUL labeling your vertex. Additionally, K gives you the NORMAL TERMS.__________________________________________________________d) The y-intercept is your C-term, so in this case, it is [0, -5].c) To find the axis of symmetry, use this formula:[tex] \frac{-b}{2a} = x[/tex]Whatever the opposite of your B-term is, you take that and divide it by twice your A-term.b) To find the vertex, in this case, you have to go from Standard Form to Vertex Form by completing the square, using this formula to get part of your new C-term:[tex][\frac{b}{2}]^{2} [/tex]When done, you get this:[tex]y = {x}^{2} + 4x + 4 \\ \\ y = [x + 2]^{2} [/tex]Then, you have to deduct some number from 4 that gave you -5 in the first place, and that integer is -9. So, here is the result:[tex]y = [x + 2]^{2} - 9[/tex]From here, we can see that our vertex is [-2, -9].a) When the binomial is set to equal to zero, you get this:[tex]{x}^{2} + 4x - 5 \\ \\ [x - 1][x + 5] = 0 \\ \\ 1, \: -5 = x[/tex]e) See above photographI am joyous to assist you anytime.