5 squirrels were found to have an average weight of 9.3 ounces with a sample standard deviation is 1.1. Find the 95% confidence interval of the true mean weight

x = 9.3 Z = 1.959964 (based from 95% confidence) n = 5 s = 1.1 upper bound of interval $$ x+z\frac{s}{\sqrt{n}}=9.3+1.959964\cdot\frac{1.1}{\sqrt{5}}\approx10.26 $$ lower bound of interval $$ x-z\frac{s}{\sqrt{n}}=9.3-1.959964\cdot\frac{1.1}{\sqrt{5}}\approx8.34 $$