(1) What is the equation, in point-slope form, for a line that goes through (8, −4) and has a slope of negative 5/6 (all fractions are negative.) A) y + 4 = - 5/6 (x + 8) B) y + 4 = - 5/6 (x - 8) C) y - 4 = - 5/6 (x + 8) "I think this is the answer but i am not too sure" D) y - 4 = - 5/6 (x - 8)(2) What is the equation of a line, in point-slope form, that passes through (−2, −6) and has a slope of 1/3? A) y - 2 = 1/3 (x - 6) B) y + 2 = 1/3 (x + 6) C) y + 6 = 1/3 (x + 2) D) y - 6 = 1/3 (x - 2)(3) What is the equation in point-slope form of the line that passes through the points (7, 5) and (−4, −1) ? A) y + 1 = 6/7 (x + 4) B) y + 4 = 11/6 (x + 1) C) y + 1 = 6/11 (x + 4) D) y - 1 = 6/11 (x - 4)(4) What is the equation in point-slope form of a line that passes through the points (7, −8) and (−4, 6) ?A) y − 6 = − 2/3 (x + 4)B) y + 6 = − 2/3 (x − 4)C) y + 6 = − 14/11 (x − 4)D) y − 6 = − 14/11 (x + 4)

Formula for point-slope: [tex]y - y1 = m(x-x1) [/tex]
Plug in the values (1): [tex]y + 4 = -\frac{5}{6} (x - 8) [/tex]  {Choice B}
Plug in the values (2): [tex]y + 6 = \frac{1}{3}(x+ 2)[/tex]  {Choice C}
_______________________

[For (3) and (4) we need to solve for slope]

(3)
First, solve for slope.
Formula for slope: [tex] \frac{y2-y1}{x2-x1} [/tex]
Plug in values: [tex] \frac{-1-5}{-4-7} = - \frac{6}{11} [/tex]
Slope: [tex]- \frac{6}{11} [/tex]
Second, we must plug into point-slope form. 
Formula for point-slope: [tex]y - y1 = m(x-x1)[/tex]
Plug in the values: [tex]y + 1 = - \frac{6}{11}(x + 4) [/tex]   {Choice C}


(4)
First, solve for slope.
Formula for slope: [tex] \frac{y2-y1}{x2-x1} [/tex]
Plug in values: [tex] \frac{6-(-8)}{-4-7} = - \frac{14}{11} [/tex]
Slope: [tex]- \frac{14}{11} [/tex]
Second, we must plug into point-slope form. 
Formula for point-slope: [tex]y - y1 = m(x-x1) [/tex]
Plug in the values: [tex]y - 6 = - \frac{14}{11}(x + 4) [/tex]   {Choice D}