There are 11 counters in a bag.. 8 of the counters are green. 3 of the counters are blue. Sid takes at random two counters from the bag. Work out the probability that Sid takes one counter of each colour.

Answer:For a green and a blue  P1 = 8/11 * 3/10 = (80 * 33) / 110^2 = .218For a blue and a green  P2 = 3/11 * 8/10 = (30 * 88) / 110^2 = .218 The probabilities are the same