PLEASE HELP, 40 points, absurd answers will be reported, good answers will get brainliest8.03b(PART 1)Find at least three examples of conic sections in the real world (marketing, architecture, nature, etc.). Make sure your collage demonstrates at least two of the conic categories you have learned. You may use circles, ellipses, parabolas, or hyperbolas. Arrange your images on paper or in a document.(PART 2)Respond to each of the following prompts in a word processing document.Write a brief description about one of the conics from your collage.Write the equation that represents your conic in its standard form. To do this either find the measurements of your conic example to create the equation or guess the measurements of the conic.Your assignment must include:Your conics collage.A description about one conic from your collage.The standard form equation of one of the conics.An explanation of how the equation for the conic was found.

Question
solved
general 4 months ago 9933

the solution for which of the following requires use of absolute value?a: At a school fundraiser, students washed twenty cars for 5$ per vehicle. Each driver donated and additional $3-$5. How much money was raised.b: A local merchant donates 10% of her sales on the first day of each month to a local cause. if her annual donations total $1500 what is her average daily sales?c: If gas cost $3.50 per gallon, how much did Celia pay to fill her tank with 8.2 gallons?d: Marissa ran a half marathon (about 13.1 miles) in 2 hours and 4 minutes. what was her speed?

Question
solved
general 4 months ago 9873

PLEASE HELP8.03a1. Find the vertices and foci of the hyperbola with equation x squared over nine minus y squared over sixteen = 1. A) Vertices: (± 5, 0); Foci: (± 3, 0) B) Vertices: (± 3, 0); Foci: (± 5, 0) C) Vertices: (0, ± 3); Foci: (0, ±5) D) Vertices: (0, ± 5); Foci: (0, ± 3)2. Find the vertices and foci of the hyperbola with equation quantity x minus three squared divided by sixteen minus the quantity of y plus four squared divided by nine = 1. A) Vertices: (7, -4), (-1, -4); Foci: (-2, -4), (8, -4) B) Vertices: (-4, 7), (-4, -1); Foci: (-4, -2), (-4, 8) C) Vertices: (6, -4), (0, -4); Foci: (0, -4), (6, -4) D) Vertices: (-4, 6), (-4, 0); Foci: (-4, 0), (-4, 6)3. Graph the hyperbola with equation A horizontal hyperbola is shown on the coordinate plane centered at, negative one, four, with vertices at, negative four, negative four and two, negative four. = 1. A) A vertical hyperbola is shown on the coordinate plane centered at the origin with vertices at, zero, two and zero, negative two. B) A horizontal hyperbola is shown on the coordinate plane centered at, negative three, three, with vertices at, negative five, three and negative 1, three. C) A vertical hyperbola is shown on the coordinate plane centered at, three, negative three, with vertices at, three, negative one and three, negative five. D) A horizontal hyperbola is shown on the coordinate plane centered at the origin with vertices at, negative two, zero and two, zero.4. Find an equation in standard form for the hyperbola with vertices at (0, ±2) and foci at (0, ±7). A) y squared over forty nine minus x squared over four = 1 B) y squared over forty five minus x squared over four = 1 C) y squared over four minus x squared over forty nine = 1 D) y squared over four minus x squared over forty five = 15. Find an equation in standard form for the hyperbola with vertices at (0, ±6) and asymptotes at y = ± three divided by four times x..

Question
solved
general 4 months ago 3935

PLEASE HELP8.021. Find the center, vertices, and foci of the ellipse with equation x squared divided by one hundred plus y squared divided by sixty four = 1. A) Center: (0, 0); Vertices: (-10, 0), (10, 0); Foci: (-8, 0), (8, 0) B) Center: (0, 0); Vertices: (0, -10), (0, 10); Foci: (0, -8), (0, 8) C) Center: (0, 0); Vertices: (-10, 0), (10, 0); Foci: (-6, 0), (6, 0) D) Center: (0, 0); Vertices: (0, -10), (0, 10); Foci: (0, -6), (0, 6)2. Find the center, vertices, and foci of the ellipse with equation 2x2 + 6y2 = 12. A) Center: (0, 0); Vertices: point negative square root of six comma zero and point square root of six comma zero ; Foci: (-2, 0), (2, 0) B) Center: (0, 0); Vertices: (0, -6), (0, 6); Foci: Ordered pair zero comma negative four square root two and ordered pair zero comma four square root two ; C) Center: (0, 0); Vertices: point zero comma negative square root of six and point zero comma square root of six ; Foci: (0, -2), (0, 2) D) Center: (0, 0); Vertices: (-6, 0), (6, 0); Foci: Ordered pair negative four square root two comma zero and ordered pair four square root two comma zero3. Graph the ellipse with equation x squared divided by twenty five plus y squared divided by four = 1. A) A vertical ellipse is shown on the coordinate plane centered at, five, two, with vertices at, five, seven, and five, negative three and minor axis endpoints at three, two, and seven, two. B) A horizontal ellipse is shown on the coordinate plane centered at five, two, with vertices at zero, two, and ten, two and minor axis endpoints at five, four and five, zero. C) A vertical ellipse is shown on the coordinate plane centered at the origin with vertices at zero, five and zero, negative five and minor axis endpoints at, negative two, zero and two, zero. D) A horizontal ellipse is shown on the coordinate plane centered at the origin with vertices at, negative five, zero and, five, zero and minor axis endpoints at, zero, two and zero, negative two.4. Find an equation in standard form for the ellipse with the vertical major axis of length 6 and minor axis of length 4. A) x squared divided by two plus y squared divided by three = 1 B) x squared divided by nine plus y squared divided by four = 1 C) x squared divided by three plus y squared divided by two = 1 D) x squared divided by four plus y squared divided by nine = 15. An elliptical riding path is to be built on a rectangular piece of property, as shown below.A vertical ellipse is shown centered on the coordinate plane, surrounded by a rectangle of equal length and width.The rectangular piece of property measures 8 mi by 6 mi. Find an equation for the ellipse if the path is to touch the center of the property line on all 4 sides.

Question
solved
general 4 months ago 5234

PLEASE HELP8.011. Find the vertex, focus, directrix, and focal width of the parabola.x2 = 20y A) Vertex: (0, 0); Focus: (0, 5); Directrix: y = -5; Focal width: 20 B) Vertex: (0, 0); Focus: (5, 0); Directrix: x = 5; Focal width: 5 C) Vertex: (0, 0); Focus: (5, 0); Directrix: y = 5; Focal width: 80 D) Vertex: (0, 0); Focus: (0, -5); Directrix: x = -5; Focal width: 802. Find the vertex, focus, directrix, and focal width of the parabola.x = 3y2 A) Vertex: (0, 0); Focus: one divided by twelve comma zero ; Directrix: x = one divided by twelve ; Focal width: 12 B) Vertex: (0, 0); Focus: the point one twelfth comma zero ; Directrix: x = negative one twelfth ; Focal width: 0.33 C) Vertex: (0, 0); Focus: zero comma one divided by sixteen ; Directrix: x = negative one divided by sixteen ; Focal width: 0.33 D) Vertex: (0, 0); Focus: one divided by sixteen comma zero ; Directrix: y = nnegative one divided by sixteen ; Focal width: 123. Find the standard form of the equation of the parabola with a vertex at the origin and a focus at (0, 9). (1 point) A) y = one divided by thirty six x2 B) y = one divided by nine x2 C) y2 = 9x D) y2 = 36x4. Find the standard form of the equation of the parabola with a focus at (0, 8) and a directrix at y = -8. A) y = one divided by thirty two x2 B) y2 = 8x C) y2 = 32x D) y = one divided by eight x25. Find the standard form of the equation of the parabola with a focus at (7, 0) and a directrix at x = -7. A) y = one divided by twenty eight x2 B) x = one divided by twenty eight y2 C) -28y = x2 D) y2 = 14x6. A building has an entry the shape of a parabolic arch 74 ft high and 28 ft wide at the base, as shown below.A parabola opening down with vertex at the origin is graphed on the coordinate plane. The height of the parabola from top to bottom is seventy four feet and its width from left to right is twenty eight feet.Find an equation for the parabola if the vertex is put at the origin of the coordinate system.

Question
solved
general 4 months ago 4549

1.) Four teachers bought an old boat for $60.The first teacher paid one-half of the sum of the amounts paid by the other teachers.The second teacher paid one-third of the sum of the amounts paid by the other teachers.The third teacher paid one-fourth of the sum of the amounts paid by the other teachers.How much did the fourth teacher pay? 2.) What is the smallest number of coins that you need so that you can give exact change for any amount from 1 cent to 99 cents? Show your work please. Any improper answers will be reported and removed- thanks!:) Have fun!

Question
solved
general 4 months ago 2498

1.) There are 8 people in a room.Each person shakes hands with each of the other people once and only once.How many handshakes take place?2.) A student has some pigs and some chickens.He finds that together they have 70 heads and 200 legs.How many pigs and how many chickens does he have? 3.) A well is 10 feet deep.A frog climbs up 5 feet during the day, but falls back 4 feet at night.Assuming that the frog starts at the bottom of the well,how many days does it take the frog to get to the top? I'm looking for work shown, too, please! :)

Question
solved
general 4 months ago 1909

The figure below shows a partially completed set of steps to construct a rhombus PQRS:The next step is to construct side PS of the figure so that side PS is parallel and congruent to side QR. The chart below shows the steps each of the four students took to draw side PS:Student 1 Fix the compass at M and adjust its width to point L. Without changing the width of the compass, move the compass to N and draw a small arc on the big arc. Label the point of intersection of the two arcs as T. Draw a line segment from P that passes through T. Adjust the width of the compass to QR and draw an arc from point P to intersect line PT at S.Student 2 Fix the compass at M and draw an arc that intersects side QP at point T. Without changing the width of the compass, move the compass to R and draw an arc. Adjust the width of the compass to QR and draw an arc from point P. Draw a line segment from R that passes through T and intersects the second arc at S.Student 3 Fix the compass at L and adjust its width to point M. Without changing the width of the compass, move the compass to R and draw an arc which intersects QR at point T. Draw a line segment from R that passes through T and intersects the arc at S.Student 4 Fix the compass at L and adjust its width to point P. Without changing the width of the compass, move the compass to R and draw an arc which intersects QR at point T. Draw a line segment from R that passes through T and intersects the arc at S.Which student used the correct steps to construct rhombus PQRS?A. Student 2B. Student 4C. Student 3D. Student 1

Question
solved
general 4 months ago 8873