The path of a football kicked by a field goal kicker can be modeled by the equation y = –0.03x2 + 1.53x, where x is the horizontal distance in yards and y is the corresponding height in yards. What is the football’s maximum height? Round to the nearest tenth. yds. How far is the football kicked? yds.

This is the equation of an upside down parabola, so the maximum height will be at the vertex. To find the vertex, we'll use the formula for the x-coordinate and then solve for the y-coordinate.
[tex]x=\frac{-1.53}{2*-.03}=25.5[/tex]

Plugging this into the given formula:
[tex]y=-0.03(25.5)^2+1.53(25.5)=19.5075[/tex]
Since it asks us to round, the maximum height would be 20 yards. To find how far the football travels in total, we need to set the equation equal to 0 and find the roots:
[tex]0=-0.03x^2+1.53x=x(-0.03x+1.53)[/tex]

Then by the zero product property (or the no zero divisors rule), we have:
[tex]x=0[/tex] (this is the x value where the ball is kicked from)
[tex]-0.03x+1.53=0[/tex]
[tex]-0.03x=-1.53[/tex]
[tex]x=51[/tex]

So the ball travels 51 yards in total.